Assembly Array and loop -

i've problem in assembly language want make loop sum element of array.
suppose array contains 10,20,30,40,50,60,70,80,90,100 have sum elements of array loop... how can this?

i'm trying this:

.model small .stack 100h .data w   dw 10,20,30,40,50,60,70,80,90,100 .code  main proc mov ax, @data mov ds, ax  xor ax, ax xor bx, bx mov cx, 10  addnos: add ax, w [bx] add bx, 2 loop addnos   ;this display mov dx, ax mov ah,2 int 21h  mov ah, 4ch int 21h main endp end main  

wrong in display print ascii (&).

edit: updated answer since code in question has been changed:

int 21h / ah=2 prints single character (note integer 1 , character '1' different values).
sum of elements in array 550, requires 3 characters print. way solve write routine converts value 550 string "550", , use int 21h / ah=9 print string. how you'd go doing has been asked several times before on stackoverflow; see e.g. this question , answers it.

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this answer original question

for future questions, note "but wrong" terrible problem description. should explain precisely in way code isn't behaving way intended.

that said, there number of problems code:

here you're initializing cx first value in x. actually, since elements in x bytes (because used db) , cx word (two bytes) you'll cx = 301h (which 769 in decimal):

mov cx, x 

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here you're moving first element of x bx on , over, instead of doing addition. , again, x contains bytes while bx word register.

top:    mov bx, [x] 

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the loop instruction decrements cx 1 , jumps given label if cx != 0. incrementing cx before loop you're creating infinite loop. also, cmp useless (and i'm not sure why you're comparing against 7 since x has 5 elements):

inc cx cmp cx, 7 loop top 

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this work values in range 0-9. if sum >=10 require multiple characters. see e.g. this answer example of how convert multi-digit number string can printed. also, you're writing word-sized register byte variable:

add bx, '0' mov [sum], bx 

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here i'm bit lost @ you're trying do. if wanted write single character stdout should use int 21h / ah = 2 / dl = character. note mov ax,4 sets ah=0 , al=4. also, should end program int 21h / ax = 4c00h:

display_:     mov dx,1     mov cx, sum     mov bx, 1     mov ax,4     int 21h     mov ax, 1     int 21h