c# - Reacting mouse click event in viewModel instead of code behind -

i have wpf app list view set via viewmodel.

i have code below handle mouse click on list view have read iot better handle in view model instead of code behind?

i have code below

xaml:

<listview ... previewmouseleftbuttonup="listview_click"> ... 

code behind:

private void listview_click(object sender, routedeventargs e) {     var item = (sender listview).selecteditem;     if (item != null)     {         ...     } } 

i tried have code below there way move view model avoiding code behind completely?

public void listview_click(object sender,routedeventargs e) {     var item = (sender listview).selecteditem;     if (item != null)     {         record record = item.datacontext record;         if (record != null)         {             myviewmodel viewmodel = ((myviewmodel)this.datacontext);             var result = viewmodel.performwork(record);         }     } } 

note: record listviewitem

thanks, nick

bind listview.selecteditem property property of type record in viewmodel (such selectedrecord) , perform work when selected record changes:

xaml:

<listview ....            selecteditem="{binding selectedrecord}"/> 

viewmodel:

private record _selectedrecord; public record selectedrecord {     { return _selectedrecord; }     set     {         _selectedrecord = value;         onpropertychanged();          // call dowork() method here         this.dowork();     } }