c - 1.7 function of K&D book . How it calculate 2^0 when p is declared as 1 -

#include<stdio.h> int power(int m,int n); main() {     int i;     for(i=0;i<10;i++)         printf("%d %d %d\n",i,power(2,i),power(-3,i));     return 0;  } int power(int base,int n) {     int i,p;     p=1;  // doubt in line     for(i=1;i<=n;++i)         p=p*base;     return p;  } 

when p declared 1 . how calculate value 2^0.yet i'm beginner of c programming can't able logic behind this.and doubt in function program how works 2^0 when p=1.thanks replay..

i'm assuming 2^0 mean inputs function power 2 , 0.

in case, n = 0, , loop doesn't run because i = 1 greater 0. in case, function returns 1 because initialized p 1, , loop didn't modify it.